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Math Quiz!

Started by Anonymous · · 👁 8 views · 36 replies

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Participants AJacob Foster11William Harris14Richard Sanders7Amy Brooks8Donna Murphy3Raymond Wilson10mistymarlin6
Richard Sanders7 Richard Sanders7 Member
22 messages
joined Aug 2022
#21 ·
Jacob Foster11 said:Give it another shot. 😉

Twenty-two... 🙂
A Anonymous VeteranOP
3.6K messages
joined May 2005
#22 ·
1st place - 39 combinations
2nd place - 38
3rd place - 37
4th - 36
5th - 35
6th - 34
7th - 33

And if I'm doing the math right, you just multiply all those together.😬
Richard Sanders7 Richard Sanders7 Member
22 messages
joined Aug 2022
#23 ·
Quote:Actually,
dejz says:
1st number - 39 combinations
2.nd number - 38
3.rd number - 37
4.th - 36
5.th - 35
6.th - 34
7.th - 33

And if I'm remembering my math right, you just multiply all those together.😬
👋 👋 since the order of the numbers doesn't actually matter, you’d take that total product and divide it by (7!) to get the real count.
Amy Brooks8 Amy Brooks8 Member
27 messages
joined Sep 2007
#24 ·
Jacob Foster11 said:Not even close. 🙂
Where on earth did you get that number from? Are you just throwing darts at a board or what?

I mean, I'm pretty sure that's how it works, I just totally fat-fingered the 19 when I was typing it out.😂
Amy Brooks8 Amy Brooks8 Member
27 messages
joined Sep 2007
#25 ·
What’s the total sum of all integers from 1 to 1,000? 🙂
I mean
1+2+3+...+999+1000= ?

EDIT: And before you ask, don't bother suggesting I just use an Excel formula or some lazy shortcut; I actually want to see the math work here.😉
Jacob Foster11 Jacob Foster11 Active Member
132 messages
joined Nov 2007
#26 ·
Joshua Davis18 said:what's the total sum of all numbers from 1 to 1000🙂
basically
1+2+3+...+999+1000= ?

500 * 1001
Jacob Foster11 Jacob Foster11 Active Member
132 messages
joined Nov 2007
#27 ·
If we have 10 apples and 20 pears, how many different ways can we distribute this fruit among six children, assuming each child gets at least one pear?
Jacob Foster11 Jacob Foster11 Active Member
132 messages
joined Nov 2007
#28 ·
Richard Sanders7 said:👋 👋 The order of numbers doesn't even matter here, so you just divide that product by (7!).

In other words, 39 plus 7. 😉
Amy Brooks8 Amy Brooks8 Member
27 messages
joined Sep 2007
#29 ·
triangle
a= 17 cm
b= 25 cm
c= 29 cm

area=?
Jacob Foster11 Jacob Foster11 Active Member
132 messages
joined Nov 2007
#30 ·
Joshua Davis18 said:triangle
a= 17 cm
b= 25 cm
c= 29 cm

area=?

cos(gamma) = (a^2 + b^2 - c^2) / (2*a*b)

A = (a * b * sin(gamma)) / 2
Jacob Foster11 Jacob Foster11 Active Member
132 messages
joined Nov 2007
#31 ·
Here is another geometry problem.
Find the area of the region under the function graph
f(x) = x^2 + 1
on the interval from -1 to 1.

EDIT:
The region is bounded by these:
y = x^2 + 1
y = 0
x = -1
x = 1
Donna Murphy3 Donna Murphy3 Member
13 messages
joined Sep 2007
#32 ·
Joshua Davis18 said:that’s just more of that junk floating around in your inbox🙄

+9604 - how many legs all those little kittens have
+1372 - how many legs all those mother cats have
+0014 - how many legs women have
____
10990 - man, that was a struggle...


I know I'm late to the party, but if they're on a Greyhound bus, you've got the driver too, so maybe it's actually 10992 legs... 😉
A Anonymous VeteranOP
3.6K messages
joined May 2005
#33 ·
Jacob Foster11 said:You totally forgot to mention how many legs each girl has. 🙄 🤣

Two, in total.
Raymond Wilson10 Raymond Wilson10 Newcomer
4 messages
joined Jul 2019
#34 ·
Jacob Foster11 said:Here's another geometry problem for you guys.
What is the area of the shape under the function graph
f(x) = x^2 + 1
on the interval from -1 to 1?

EDIT:
So, the shape is bounded by these:
y = x^2 + 1
y = 0
x = -1
x = 1

integral(x^2+1) from -1 to 1 = 8/3

Unless I messed something up and did some stupid math..
Amy Brooks8 Amy Brooks8 Member
27 messages
joined Sep 2007
#35 ·
Donna Murphy3 said:I know I'm late to the party, but if they're all crammed onto a Greyhound, you've got to count the driver too—so that's another set of feet in the mix. 😉

The bus driver didn't make the cut—he's currently on a break, taking a quick pit stop in the restroom.
mistymarlin6 mistymarlin6 Member
32 messages
joined Jul 2007
#36 ·
1+2+3+4+5+...+1995+996+996+998+999+1000=1000*500+5 00

That’s how it should work out, assuming I haven't misplaced a zero somewhere along the way... is this actually right??
Donna Murphy3 Donna Murphy3 Member
13 messages
joined Sep 2007
#37 ·
Joshua Davis18 said:The bus driver isn't mentioned, he’s just on break, probably in the restroom

Right, he wasn't mentioned. But if they weren't aiming at him, then those girls—or boys, depending on which version of the story I heard—could have been out in a park, at a playground, on some beach, or up on a cliffside, or who knows where else... But since they're inside the bus, it's implied the driver is there too. Honestly, it took me like half an hour... (embarrassing truth) to figure this one out...

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