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How to calculate pixel size

Started by driftingraven14 · · 👁 4 views · 6 replies

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Participants driftingraven14Edward Stewartironcyclist58Kenneth Cruz67
driftingraven14 driftingraven14 NewcomerOP
3 messages
joined Jan 2018
#1 ·
Hi there,

I was wondering if someone might be able to walk me through how to calculate the pixel size if I'm working with an image that has a resolution of 4928x3264 (Length x Width), especially since both the horizontal and vertical resolutions are set at 72 dpi.

Thanks so much in advance! 🙂
Edward Stewart Edward Stewart Member
44 messages
joined Feb 2013
#2 ·
There isn't much to calculate here, really, because pixel size depends entirely on the specific medium or screen you're viewing it on—or perhaps the way the question is being framed might be slightly off 🙂.
An image is fundamentally composed of pixels (those tiny little dots), and in this particular instance, we are looking at 3264 x 4928 (Length x Width)
. If what you're actually curious about is the physical print size at a density of 72 dpi (dots per inch, or 72 dots per inch), then you would be looking at roughly 68.44 x 45.33 inches, which translates to about 173.4 x 115.15 cm.

For example, if you were aiming for standard high-quality color printing, you'd typically utilize 200-300 dpi; this means an image up to about 24x16 inches would look quite sharp, whereas anything larger than that and you'd start to notice those individual pixels, creating a certain graininess.
driftingraven14 driftingraven14 NewcomerOP
3 messages
joined Jan 2018
#3 ·
Edward Stewart said:There isn't much to calculate here, really, because pixel size depends entirely on the specific medium or screen you're viewing it on—or perhaps the way the question is being framed might be slightly off 🙂.
An image is fundamentally composed of pixels (those tiny little dots), and in this particular instance, we are looking at 3264 x 4928 (Length x Width)
. If what you're actually curious about is the physical print size at a density of 72 dpi (dots per inch, or 72 dots per inch), then you would be looking at roughly 68.44 x 45.33 inches, which translates to about 173.4 x 115.15 cm.

For example, if you were aiming for standard high-quality color printing, you'd typically utilize 200-300 dpi; this means an image up to about 24x16 inches would look quite sharp, whereas anything larger than that and you'd start to notice those individual pixels, creating a certain graininess.

I might have phrased my question a bit clumsily.
When I check the image properties, I see values for 4928x3264 (Length x Width) and 72 dpi.

But what I'm actually trying to figure out is how to reach the Apple pixel size value (which I've highlighted in red). Right now, I can see the value there, but since I occasionally need to calculate it myself from scratch, I was wondering if anyone could walk me through the process of how to get it. 🙂
Edward Stewart Edward Stewart Member
44 messages
joined Feb 2013
#4 ·
I’m struggling to find the context here; perhaps we are simply dealing with a bit of semantic confusion regarding how these terms are applied. A pixel is fundamentally just a single dot within an image, possessing no inherent physical dimension of its own. What people often refer to as the pixel size is merely a calculated result—essentially just the ratio between that digital data and the actual physical surface, be it a sheet of paper or a computer monitor, upon which you happen to be viewing the image.
One could just as easily approach the problem from the opposite direction... say, you’re in the middle of designing some large-scale poster and you find yourself wondering, "What specific resolution do I actually need to ensure that one tiny detail hits exactly half a millimeter on the printed page?" Even then, you aren't really looking for a magic number or a special dimension; you're still fundamentally tethered to the same relationship with resolution. It all circles back to the same principle.

When one considers the nature of a digital image, it is important to recognize that its true identity is defined solely by its resolution; everything else is merely supplementary data. Take DPI, for instance—it functions essentially as a bit of contextual information, much like a footnote. If you were to scan a physical document using a high-end scanner from an office in Chicago, for example, the DPI would simply tell you the density of that transfer. A setting of 72 DPI implies that you have effectively mapped 1/72 of an inch onto a single pixel of the image. It is a measure of how that physical space was translated into the digital realm, nothing more and nothing less.
driftingraven14 driftingraven14 NewcomerOP
3 messages
joined Jan 2018
#5 ·
Edward Stewart said:I’m struggling to find the context here; perhaps we are simply dealing with a bit of semantic confusion regarding how these terms are applied. A pixel is fundamentally just a single dot within an image, possessing no inherent physical dimension of its own. What people often refer to as the pixel size is merely a calculated result—essentially just the ratio between that digital data and the actual physical surface, be it a sheet of paper or a computer monitor, upon which you happen to be viewing the image.
One could just as easily approach the problem from the opposite direction... say, you’re in the middle of designing some large-scale poster and you find yourself wondering, "What specific resolution do I actually need to ensure that one tiny detail hits exactly half a millimeter on the printed page?" Even then, you aren't really looking for a magic number or a special dimension; you're still fundamentally tethered to the same relationship with resolution. It all circles back to the same principle.

When one considers the nature of a digital image, it is important to recognize that its true identity is defined solely by its resolution; everything else is merely supplementary data. Take DPI, for instance—it functions essentially as a bit of contextual information, much like a footnote. If you were to scan a physical document using a high-end scanner from an office in Chicago, for example, the DPI would simply tell you the density of that transfer. A setting of 72 DPI implies that you have effectively mapped 1/72 of an inch onto a single pixel of the image. It is a measure of how that physical space was translated into the digital realm, nothing more and nothing less.


Thanks for clarifying. 🙂 Yeah, I suppose a pixel is essentially like a dot; it doesn't have a dimension of its own, so it isn't something you can measure directly.
The software actually spits out the data I mentioned earlier, but now I'm stuck having to manually calculate the pixel size myself because the program keeps flagging it as UNKNOWN. So, I was really just hoping there might be some direct link between those two values that I was missing.

And to make matters even more confusing, my Apple length shows up as 0 for this specific case, which honestly makes absolutely no sense at all. 🤔
ironcyclist58 ironcyclist58 Regular
863 messages
joined Feb 2020
#6 ·
The pixel size listed in the table refers to the actual physical dimensions of a single pixel on the camera sensor...
Kenneth Cruz67 Kenneth Cruz67 Regular
376 messages
joined Oct 2017
#7 ·
When you're working with a metric photograph, I guess the pixel size really becomes a crucial factor to consider. For instance, if you were to photograph a car that is about 6.5 feet long and that image ends up being mapped across 20 pixels, then each individual pixel would effectively represent a dimension of roughly 4 inches.

So, I think what the software is actually spitting out when it shows you those micrometer measurements is just the specific pixel size on the camera sensor itself. If you take a sensor that's, say, about half an inch by half an inch and it captures something like 1000x1000 pixels, then I guess the pixel size would work out to be roughly 0.001 mm.

I guess it’s worth mentioning that 72 dpi is really just the standard screen resolution, so you could say that every single monitor out there displays images at about 72 dpi.

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